Question 279776
Complete the square in x and y.
{{{ x^2+y^2-6x + 10y +24 = 0 }}}
{{{x^2-6x+y^2+ 10y +24 = 0}}}
 {{{(x^2-6x+9)+(y^2+ 10y +25)+24 = 9+25 }}}
{{{(x-3)^2+(y+5)^2+24 = 34 }}}
{{{(x-3)^2+(y+5)^2 = 10 }}}
The general equation for a circle centered at (h,k) with a radius R is:
{{{(x-h)^2+(y-k)^2=R^2}}}
This circle is centered at (3,-5).