Question 279769
Solve for 't'

A=Be^-kt
{{{e^(-kt) = A/B}}}
{{{(e^(-k))*(e^t) = A/B}}}
{{{e^t = (A/B)*e^(k)}}}
{{{t = ln(A/B) + ln(k)}}}
or {{{t = ln(Ak/B)}}}