Question 279705
Two general rules are
{{{a^(-b) = 1/a^b}}}and
and
{{{a^(b/c) = (a^(1/c))^b)}}}
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applying these rules,
{{{(-32)^(-3/5) = 1/(-32)^(3/5)}}}
and
{{{1/(-32)^(3/5) = 1/((-32)^(1/5))^3}}}
Note that the fifth root of {{{-32}}} is {{{-2}}} because
{{{-2*-2*-2*-2*-2 = -32}}}, so
{{{ 1/((-32)^(1/5))^3 = 1/(-2)^3}}}
{{{1/(-2)^3 = 1/(-8)}}}
{{{1/(-8) = -1/8}}} answer