Question 279725
(n-3)(n-4)-3(n+2)(n-3)
---------
= n^2-3n-4n+12 -3[n^2-3n+2n-6]
---
= n^2 - 7n + 12 -3n^2 + 9n-6n + 18
--
= -2n^2 -4n + 30
======================
Cheers,
Stan H.