Question 279569
{{{3x-5 over x^2-25 - 2 over x+5}}}
{{{(3x-5)/(x^2-25) - 2/(x+5)}}}
Common DEN = x^2 - 25 = (x-5)*(x+5)
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= {{{(3x-5)/(x^2-25) - 2*(x-5)/(x^2-25)}}}
= {{{((3x-5) - 2*(x-5))/(x^2-25)}}}
= {{{(3x-5 - 2x+10)/(x^2-25)}}}
= {{{(x+5)/(x^2-25)}}}
= {{{(x+5)/((x-5)*(x+5))}}}
= 1/(x-5)