Question 279354
Let {{{d}}} = number of dimes
Let {{{n}}} = number of nickels
given:
{{{10d + 5n = 195}}}
{{{n + d = 28}}}
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{{{d = 28 - n}}}
and
{{{10*(28 - n) + 5n = 195}}}
{{{280  - 10n + 5n = 195}}}
{{{5n = 280 - 195}}}
{{{5n = 85}}}
{{{n= 17}}}
and
{{{n + d = 28}}}
{{{17 + d = 28}}}
{{{d = 11}}}
They have 17 nickels and 11 dimes
check answer:
{{{10d + 5n = 195}}}
{{{10*11 + 5*17 = 195}}}
{{{110 + 85 = 195}}}
{{{195 = 195}}}
OK