<PRE><B>Question 279236</B>
You gave a point and a line.
What is your question?
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Common problems are:
Find the equation thru the point and parallel to the line.
Find the equation thru the point and perpendicular to the line.
Find the distance from the point to the line.
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A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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Find the slope of the line.  Do that by putting the equation in slope-intercept form, y = mx + b.  That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
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The slope of lines parallel have the same slope.
The slope of lines perpendicular is the negative inverse, m = +1/3
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Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
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