Question 279231
Find the area of a regular hexagon with the given measurement.
4-inch side
A = sq. in.

from http://www.mathopenref.com/polygonregulararea.html: 
{{{ area = (S^2 * N)/(4 * tan(pi/N)) }}}
where
S  is the length of any side
N  is the number of sides
{{{ pi }}} is PI, approximately 3.142
TAN  is the tangent function calculated in radians

{{{ area = (4^2 * 6)/(4 * tan(pi/6)) }}}
{{{ area = (16 * 6)/(4 * sqrt(3)/3) }}}
{{{ tan(pi/6) = sqrt(3)/3 = approximately 0.57735027 }}}
{{{ area = 96/(4 * sqrt(3)/3) }}}
{{{ area = 24/(sqrt(3)/3) }}}
{{{ area = 24 * 3/sqrt(3) }}}
{{{ area = 72/sqrt(3) }}}
{{{ area = (72 * sqrt(3))/3 }}}
{{{ area = 24sqrt(3) }}}
{{{ area = approximately 41.569 square inches }}}