Question 279094
Brittany can run a mile in 6 minutes and Christina can run a mile in 9 minutes. If both Brittany and Christina start running at the same time and Brittany starts 1/3 of a mile behind Christina, how long will it take Brittany to catch up with Christina?
I know that Brittany runs at 1/6 miles per minute, Christina runs at 1/9 miles per minute, and distance is rate multiplied by time.
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Brittany DATA:
distance = [x+(1/3)] miles ; rate = (1/6)mi/min ; time = [(3x+1)/3]/(1/6) = 
2(3x+1) = 6x+2 min

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Christina DATA;
distance = x mile rate = 1/9 mi/m ; time = x/(1/9) = 9x min
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Equation:
time = time
6x+2 = 9x
3x = 2
x = 2/3
Brittaney's time = 6 min = Christina's time
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Cheers,
Stan H.