Question 278965
{{{system((1/5)x - (1/4)y = 3,
(2/5)x + (1/2)y = 2)}}}
<pre><font size = 4 color = "indigo"><b>
Clear of fractions FIRST BEFORE you try to solve the system.

Clear the first equation of fractions by multiplying
every term on both sides by {{{LCD=red(20)}}}:

{{{red("20")*(1/5)x - red("20")*(1/4)y = red("20")*3}}}

{{{4x - 5y = 60}}}

Clear the second equation of fractions by multiplying
every term on both sides by {{{LCD=red(10)}}}:

{{{red("10")*(2/5)x + red("10")*(1/2)y = red("10")*2}}}

{{{4x + 5y = 20}}}

So now you have the easy to solve system:

{{{system(4x - 5y = 60,
4x + 5y = 20)}}}

And the solution is {{{x=10}}}, {{{y=-4}}}

Edwin</pre>