Question 278655
From your equation, I can see that this is a quadratic equation becuase the biggest exponent is 2.  Since the value in front of the x^2 term is negative, we have an upside down parabola.

I will make 4 points for you to graph on the xy-plane.
I will pick different values for x.  

Let x = 0

y = -2(0)^2

y = 0

Our first point is (0,0).

Let x = 1

y = -2(1)^2

y = -2(1)

y = -2

Our second point is (1,-2).

Let x = -3

y = -2(-3)^2

y = -2(9)

y = -18

Our third point is (-3,-18).

How about one more point?

Let x = -4

y = -2(-4)^2

y = -2(16)

y = -32

Our fourth point is (-4,-32).


You have four points.  Now, you can plot them on the xy-plane.