<PRE><B>Question 278558</B>
an aircraft flew 2 hours with the wind. the return trip took 3 hours against the wind.
 if the speed of the plane in still air is 164 miles per hour more than the
 speed of the wind, find the wind speed and the speed of the plane in still air
:
(164 + w) = aircraft speed in still air
then
164 = aircraft speed against wind
and
(164 + 2W) = aircraft speed with the wind
:
The two trips are equal distance, write a distance equation
:
2(164+2W) = 3(164)
328 + 4W = 492
4W = 492 - 328
4W = 164
W = {{{164/4}}}
W = 41 mph is the speed of the wind
then
164 + 41 = 205 mph is speed of the plane
:
:
Check solutions by finding the distance, they should be equal
2(205+41) = 492 mi
3(205-41) = 492
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