Question 278492
Let x=percent of acid in resulting mixure
Now we know that the percent of acid in the 80% solution (0.80*2)+the percent of acid in the 20% soluton(0.20*6)=the amount of acid in the resulting mixture (x*8).  So our equation to solve is:

0.80*2+0.20*6=8x
1.6+1.2=8x
2.8=8x
x=0.35 or 35%

Hope this helps--ptaylor