Question 278497
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Solve *[tex \LARGE S\ =\ 2B\ +\ Ph] for *[tex \LARGE P]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2B\ +\ Ph\ =\ S]


Add *[tex \LARGE -2B] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ph\ =\ S\ -\ 2B]


Multiply both sides by *[tex \LARGE \frac{1}{h}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ \frac{S\ -\ 2B}{h}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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