Question 278346
Pls. help me to solve this equation: Find the vertex of {{{y = 3x^2 + x - 2}}}
<pre><font size = 4 color = "indigo"><b>
The x-coordinate of the vertex of the graph of a quadratic 
is found by the formula:

x-coordinate of vertex of {{{ax^2+bx+c}}} is {{{-b/(2a)}}}

So the x-coordinate of the graph of your quadratic equation is 

{{{-b/(2a)=-1/(2*3)=-1/6}}}

To find the y-coordinate of the vertex, substutite the
x-coordinate for the vertex into the oeriginal equation:

{{{y = 3x^2 + x - 2}}}

{{{y = 3(-1/6)^2 + (-1/6) - 2}}}

{{{y = 3(1/36)-1/6-2}}}

{{{y=1/12-1/6-2}}}

{{{y=1/12-2/12-24/12}}}

{{{y=(-25)/12}}}

So the vertex is the point ({{{-1/6}}},{{{-25/12}}})

Edwin</pre>