Question 278242
{{{m(m-6)=27}}} Start with the given equation.



{{{m^2-6m=27}}} Distribute



{{{m^2-6m-27=0}}} Subtract 27 from both sides.



{{{(m-9)(m+3)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{m-9=0}}} or  {{{m+3=0}}} 


{{{m=9}}} or  {{{m=-3}}}    Now solve for m in each case



So our answers are 


 {{{m=9}}} or  {{{m=-3}}}