Question 278233
{{{4y^2-11y=3}}} Start with the given equation



{{{4y^2-11y-3=0}}} Subtract 3 from both sides.



{{{(y-3)(4y+1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{y-3=0}}} or  {{{4y+1=0}}} 


{{{y=3}}} or  {{{y=-1/4}}}    Now solve for y in each case



So our answers are 


 {{{y=3}}} or  {{{y=-1/4}}}