Question 33846
THe formula can be measured by:
{{{x=x[0]10^((y[1]-y[0])/10)}}}
SUch as a normal conversation is 60dB and a car horn is 110dB
and we want to find how many times as loud as a normal conversation is a car horn.
Eqaution:
y=110, y<sub>0</sub>=60 so:
{{{x=x[0]10^((110-60)/10)}}}
{{{x=x[0]10^5}}}
x=100000
Hence, it is 100000 intensive.
PAul.