<PRE><B>Question 278185</B>
write an equation for the line that is perpendicular to the given line and that passes through the given point
y=x-3;(4,6) 
Given line slope is 1; slope of the perpendicular line must be -1
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Equation Form: y = mx + b
6 = -4 + b
b = 10
Equation:
y = -x + 10
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and 
find the slope of a line perpendicular to the graph of each equation y=-3x
The Given line has slope = -3
Any line perpendicular to it  has slope = 1/3
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Cheers,
Stan H.</PRE>