Question 278191
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-1,-2\right)]. So this means that {{{x[1]=-1}}} and {{{y[1]=-2}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,-2\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=-2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-2--2)/(3--1)}}} Plug in {{{y[2]=-2}}}, {{{y[1]=-2}}}, {{{x[2]=3}}}, and {{{x[1]=-1}}}



{{{m=(0)/(3--1)}}} Subtract {{{-2}}} from {{{-2}}} to get {{{0}}}



{{{m=(0)/(4)}}} Subtract {{{-1}}} from {{{3}}} to get {{{4}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-1,-2\right)] and *[Tex \LARGE \left(3,-2\right)] is {{{m=0}}}