Question 278185
passes through the given point
y=x-3;(4,6) and

slope of any line perpendicular to a given line of slope m =-1/m since their slopes product must be equal to -1.
y =x-3.
slope m =1.
slope a  kine perpenducolr to this line =-1/1 =-1.
(4,6)
y-y1=m(x-x1)
y-6= -1(x-4)
y-6== -x+4
y+x-10 =0.
find the slope of a line perpendicular to the graph of each equation y=-3x
slopof y =-3x m =-3.
as said above slope of a line perpendiculr to y =-63x is -1/-3 =1/3.