Question 30954
You have a great start to your solution.  You've done most of the steps correctly!  

Before I finish this problem, let's review what 1/x^-1 is.  When you have anything to the -1 power. that means the inverse of what you have.  So the inverse of 1/x^-1 is x/1.  If you had x^-1, the inverse would be 1/x.  If you have the negative sign in the exponent, you won't have to add a negative sign to the number. BAsically, all you have to do is move the number to the top or bottom to get rid of the negative sign.  


{{{16x^3*y/-4xy^3*2xy/(-x^-1)}}}
{{{-4x^2/y^2*2xy*(-x)}}}
{{{(-8x^3y)*(-x)/(y^2)}}}
{{{8x^4y/y^2}}}
{{{8x^4/y}}}