Question 277879
Solve for x:
{{{Log[5](Log[2](x)) = 1}}}
Recall the definition of the logarithm of a number (variable).
"The logarithm of a number (variable) is the power to which the base must be raised to equal that number (variable)" or...
{{{Log[b](x) = y}}} can be expressed as: {{{x = b^y}}}
So you can express the given logarithm as...
{{{Log[2](x) = 5^1}}} or 
{{{Log[2](x) = 5}}} applying the rule again...
{{{x = 2^5}}} or...
{{{highlight(x = 32)}}}