Question 277712
let x="amount @ 5%", y="amount @ 6%", and z="amount @ 6.5%"


x + y + z = 36000


x(5%) + y(6%) + z(6.5%) = 2190


3y = x + z


substituting ___ (3y) + y = 36000 ___ y = 9000


x + z = 27000


x(5%) + z(6.5%) = 1650


you can find x and z using the last 2 equations