Question 277701
if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second interger. find the third interger

Let the numbers be x, x+2 and x+4


x+(x+4)+87=5(x+2)

2x+4+87=5x+10

2x-5x=-4-87+10

-3x=-81

x= 27

the other two numbers are 89 and 91