Question 277104
Assume the problem is:
{{{x/(x^2-16)}}} - {{{4/(x^2+ 5x + 4)}}}
Factor the denominators
{{{x/((x-4)(x+4))}}} - {{{4/((x+4)(x+1))}}}
the common denominator: (x-4)(x+4)(x+1)
:
{{{(x(x+1) - 4(x-4))/((x-4)(x+4)(x+1))}}} = {{{(x^2+x-4x+16)/((x-4)(x+4)(x+1))}}} = {{{(x^2-3x+16)/((x-4)(x+4)(x+1))}}}; about all you can do with it