Question 277614


{{{x^3-3x^2+4x-12}}} Start with the given expression



{{{(x^3-3x^2)+(4x-12)}}} Group like terms



{{{x^2(x-3)+4(x-3)}}} Factor out the GCF {{{x^2}}} out of the first group. Factor out the GCF {{{4}}} out of the second group



{{{(x^2+4)(x-3)}}} Since we have the common term {{{x-3}}}, we can combine like terms



So {{{x^3-3x^2+4x-12}}} factors to {{{(x^2+4)(x-3)}}}



In other words, {{{x^3-3x^2+4x-12=(x^2+4)(x-3)}}}