Question 277519
{{{ log(25,5)}}}
There are 2 ways to do thia.  One is to recognize that 5^2 = 25, so
25^(1/2) = 5

--> {{{ log(25,5) = 1/2}}}
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The other way is base change.
{{{ log(25,5) = log(5)/log(25)}}}
= 0.5
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Using the base change method will always work.
If the problem had been:
{{{ log(26,5)}}} or {{{ log(25,6)}}}
then the 1st method is no help.