Question 277419
a private airplane leaves an airport and flies due south at 192km/h. Two hours later a jet leaves the same airport and flies due south at 960km/h. When will the jet overtake the plane?

Let the distance at which they meet be x

In two hours the plane would have traveled 192*2 = 384 kms.

The time taken for plane to travel x-384 kms is the same as taken by jet when they meet.

time taken by plane = x- 384/192

The time taken by the jet = x/960 

x-384/192 = x/960

960x -368640 = 192x

960x-192x= 368640

768x=368640

x= 480 kms. or 480/960 = 1/2 hour. The jet will overtake after half hour