Question 277283


{{{3x-6y=8}}} Start with the given equation.



{{{-6y=8-3x}}} Subtract {{{3x}}} from both sides.



{{{-6y=-3x+8}}} Rearrange the terms.



{{{y=(-3x+8)/(-6)}}} Divide both sides by {{{-6}}} to isolate y.



{{{y=((-3)/(-6))x+(8)/(-6)}}} Break up the fraction.



{{{y=(1/2)x-4/3}}} Reduce.



So the equation {{{y=(1/2)x-4/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=1/2}}} and the y-intercept is {{{b=-4/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{4}{3}\right)]