Question 33772
Let the number of nickels be x
Let the number of pennies be y
Let the number of dimes be z
Now z=x+y
FIrst equation:
z+x+y=16
Subsittue for z:
x+y+x+y=16
y=8-x (subsitution)
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Second Equation:
10(z)+(y)+5(x)=108
Subsittue for z:
10(x+y)+y+5x=108
10x+10y+y+5x=108
Subsitute for y:
15x+11(8-x)=108
15x+88-11x=108
4x=20
x=5
y=8-5
y=3
z=3+5
z=8
Hence, there are 8 dimes, 3 pennies and 5 nickels.
Paul.