Question 4435
In this formula, {{{f(x-2) = (x+3)?(x-4)}}}, in order to get f(5), you will have to let x= 7.  Then when you let x=7, you'll have 


{{{f(7-2) = f(5) = (7+3)/(7-4)}}}  so {{{f(5) = 10/3}}}


Please accept my apologies to the student who wrote Question # 4436.  In my attempt to answer the question, I accidentally deleted the question, and I can't get it back.  However, here is the question:


logarithm/4436: some of the values of the functions F an G are in the table. the value of G(f(3)) is Values 
x  1,2,3,4 
f(x) 3,1,4,2 
G(X)3,4,2,1


And this is the solution to that question:

It might help to write this in the following way, so corresponding values line up better:


x = 1, 2, 3, 4
f = 3, 1, 4, 2
G = 3, 4, 2, 1


First, in order to find G(f(3)}, you need to start by finding f(3).  This notation means that x=3, so look for the f value that corresponds to x=3.  At x=3, right below that you will find that f(3)=4.


So, G(f(3)) = G(4), which means to look in the G row, across to where x=4.  If x=4, the G(4) = 1, so the final answer is 1. 


Sorry about the deletion.  However, what you got is TWO for the price of ONE. 


R^2 from SCC