Question 277250
logx=1-log(x-3)

log x + log (x-3) = 1
log (x*(x-3)) = 1

If the base is 10 then we have by definition of a log:

x*(x-3) = 10^1

x^2 - 3x = 10

x^2 - 3x - 10 = 0

(x-5)*(x+2) = 0

x-5 = 0 or x+2 = 0 so

x = 5 and/or x = -2