Question 277215
im guessing u mean this, but please next time please specify what is under the radical.
{{{sqrt(5x+6)=x}}}square both sides
{{{(sqrt(5x+6))^2=(x)^2}}}
{{{5x+6=x^2}}}subtract
{{{0=x^2-5x-6}}}factor
{{{x-3=0}}}{{{x-2=0}}}
{{{x=3}}}or{{{x=2}}}
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if x=3
{{{sqrt(5(3)+6)=3}}}
{{{sqrt(9)=3}}}
{{{3=3}}} correct
if x=2
{{{sqrt(5(2)+6)=2}}}
{{{sqrt(4)=2}}}
{{{2=2}}} correct
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im not clear if thats what u were trying to solve