Question 277136
for JG to be parallel to RQ, the two sides (PQ and PR) must be divided in equal ratios by JG
___ this is the same ratio as JG/RQ


PJ / (PJ + JR) = JG / RQ


(8x - 5) / (8X - 5 + x) = 8 / 10 ___ 80x - 50 = 72x - 40 ___ 8x = 10 ___ x = 5/4


PG / (PG + QG) = JG / RQ


(3y + 2) / (3y + 2 + y) = 8 / 10 ___ 30y + 20 = 32y + 16 ___ 4 = 2y ___ 2 = y