<PRE><B>Question 276918</B>
An angry construction worker throws his wrench downward from a height of 128 feet with an initial velocity of 32 feet per second. 
The height of the wrench above the ground after 6 seconds is given by 
S(t) = -16t^2 -32t +128. 
What is the height after 1 second?
S(1) = -16-32+128 = 80 ft.
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How long does it take for the wrench to reach the ground?
Solve -16t^2 -32t + 128 = 0
Divide thru by -16 to get:
t^2 + 2t - 8 = 0
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(t+4)(t-2) = 0
Positive solution:
t = 2 seconds 
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Cheers,
Stan H.
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