Question 276783
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A number:  *[tex \Large x]


Half of the number:  *[tex \Large \frac{x}{2}]


The reciprocal of half of the number:  *[tex \Large \frac{2}{x}]


The reciprocal of the number:  *[tex \Large \frac{1}{x}]


Half of the reciprocal of the number:  *[tex \Large \left(\frac{1}{2}\right)\left(\frac{1}{x}\right)\ =\ \frac{1}{2x}]


Add the two quantities because one is increased by the other:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2}{x}\ +\ \frac{1}{2x}\ =\ \frac{1}{2}]


because "is" means equals, despite what Bill Clinton thinks.


Now just solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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