Question 276651
*[Tex \LARGE \frac{24x^3+3}{2x+1} = \frac{3(8x^3+1)}{2x+1} = \frac{3(2x+1)(4x^2-2x+1)}{2x+1} = 3(4x^2-2x+1) = 12x^2-6x+3]


Answer: *[Tex \LARGE \frac{24x^3+3}{2x+1} = 12x^2-6x+3]