Question 276438
C = Cody's age
E = Evan's age
C = 2E  :: Cody is twice as old as Evan.
Three years ago can be shown as:
C -3 = Cody's age 3 years ago
E -3 = Evan's age 3 years ago
C-3 + E-3 = 27  :: Given
C + E = 33
Substituting C = 2E
2E + E = 33
3E = 33
E = 11
Therefore
C = 2E = 22
How old were they 3 years ago?
C-3 = 19
E-3 = 8
Was the sum of their ages 27 back then?
19 + 8 = 27 ??
Yes.
Answer:
Cody's age is 22.
Evan's age is 11.
.
J = Jack's age
L = Lacy's age
J = 2L
In three years, their ages will be:
J+3 and L+3
Then the sum will be 54.
J+3 + L+3 = 54
J + L = 48
Substitue J = 2L
2L + L = 48
3L = 48
L = 16
J = 2L = 2(16) = 32
How old will they be in 3 years?
J = 35
L = 19
Will the sum of their ages be 54 then?
35 + 19 = 54 ??
Yes.
Answer:
Jack's age is 32 and Lacy's age is 16.
.
Done