Question 276406
Given that P(A or B) = 1/3, P(A) = 1/6, and P(A and B) = 1/8, find P(B).
7/24 is the answer but I would really love to know why
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General Formula: 
P(A or B) = P(A) + p(B) - P(A and B)
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Substitute:
1/3 = (1/6) + P(B) - 1/8
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Multiply thru by 24 to get:
8 = 4 + 24P(B) - 3
24P(B) = 7
P(B) = 7/24
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Cheers,
Stan H.
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