<PRE><B>Question 276339</B>
A binomial distribution has n=1580 and p=0.798. Find the mean of this distribution to the nearest tenth. Find the variance and standard deviation of this distribution to the nearest hundredth. Find the minimum and maximum usual values of mu +- 2 r
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mean = np = 
variance = npq = 
std = sqrt(npq) = 
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u-2std = np - 2sqrt(npq) = 
u+2std = np + 2sqrt(npq) = 
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Cheers,
Stan H.</PRE>