Question 276335
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Since the shorter piece is *[tex \Large x], the longer piece must be *[tex \Large 3x\ +\ 2].  Presuming an infinitely thin saw so that there is no saw kerf:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 2\ +\ x\ =\ 6]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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