Question 276256
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The circumference of the circle is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 20\pi]


But you only have to travel half of the circumference to get past the city, so the distance traveled on the circular road would be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10\pi]


Since distance equals rate times time, *[tex \Large d\ =\ rt], time can be determined by dividing distance by rate: *[tex \Large t\ =\ \frac{d}{r}]


Hence, the time, in hours, to go around the city is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{10\pi}{65}]


Since there are 60 minutes in one hour, the time in minutes to go around the city is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{10\pi}{65}\,\cdot\,60]


The path straight through the city is 20 miles and the time, in hours, to travel 20 miles at 35 mph is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{20}{35}]


And then in minutes:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{20}{35}\,\cdot\,60]


You get to do your own arithmetic.  Use 3.14 for *[tex \Large \pi] -- that is plenty close enough.  Don't forget to round to the nearest minute.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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