Question 33704
Y= x^2 - 5x + 6
=> Y = (x-3)(x-2)
x-intercepts are where Y=0
Y=0 for x=3 or x=2
So, it has two x-intercepts;
Y= x^2 - 5x + 6
=> y = (x-5/2)^2 - 1/4
The Vertex is at 5/2, -1/4) - below x-axis
*** Your answers are absolutely correct ****
Y= -X + 2x - 1 is not a parabola