Question 276085
Please help me to solve the following problem:
{{{12^(n+1)*9^(n-2)*3^n/18^(2n-1)}}}
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Factor everything
{{{12^(n+1)*9^(n-2)*3^n/18^(2n-1)}}}
= {{{2^(2n+2)*3^(n+1)*3^(2n-4)*3^n/(2^(2n-1)*3^(4n-2))}}}
Add exponents of 2's and 3's
= {{{2^(2n+2)*3^(4n-3)/(2^(2n-1)*3^(4n-2))}}}
= {{{2*3^(-1)}}}
= 2/3