Question 275967
12/sqrt5x+6 = sqrt2x+5 

144 / 5x+6 = 2x+5
(2x+5)(5x+6)= 144

10x^2+12x+25x+30=144

10x^2+37x-114=0

The factors are not integers

so you have to find the roots of the equation

x1,x2 = -b + / - {sqrt(b^2-4ac)}  / 2a

a= 10 b=37 and c=-114

x1= -b+{sqrt(b^2-4ac)}  / 2a

= -37+sqrt(1369+4560)  / 20
x1=2

x2= -b-{sqrt(b^2-4ac)}  / 2a

x2= -114/20
x2= -5.7

2 & -5.7 are the roots of the equation