<PRE><B>Question 275984</B>
 cyclist travels 30mi in 3 hours going against the wind and 80mi in 5 hours with wind. What is the rate of the cyclist in still air and what is the rate of the wind?

let speed of wind be x
let cycle rate in still air be y

Distance / rate = time

30 /y-x = 3
or y-x=10

AND
80 / x+y= 5
or
x+y = 80/5
x+y= 16


y-x=10
x+y=16

therefore 2y= 26
y=13 mph

x=3 mph




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