Question 275838
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Step 1:  Determine the slope of the line represented by the given equation.  Put the given equation into slope-intercept form:  Add *[tex \Large -x] to both sides, then multiply both sides by *[tex \Large \frac{1}{8}].  Once the given equation is in slope-intercept form, the slope of the line will be equal to the coefficient on *[tex \Large x].


Step 2:  Use the point-slope form of the equation of a line, namely:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the slope calculated in Step 1.  You can use the same slope number because parallel lines have equal slopes, in other words:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


Step 3:  Once you have plugged in the values for the coordinates of the given point and for the calculated slope, solve the resulting equation for *[tex \Large y] (similar to the process used to rearrange the equation in step 1) to put the desired equation into slope-intercept form.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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