<PRE><B>Question 275802</B>
I am not sure how to solve this: The perimeter of a rectangle is 50 centimeters. the length is 9 centimeters more than the width. Find the length and the width of the rectangle.

LET THE WIDTH BE X

the length will be 9 more than width = x+9

Perimeter = 2*l + 2*W

2*(x+9) + 2* x= 50

2x+18 +2x=50

4x= 50-18
4x=32
x= 8  cms

length= 8 +9= 17 cms

</PRE>