Question 275548
simplify -1/(3+i) using imaginary numbers
-------------
"Simplified" in this case means "no imaginary numbers in the denominator".
----------------------
So, multiply numerator and denominator by the conjugate of 3+i, which is 3-i.
---
You get:
[-1(3-i)]/[(3+i)(3-i)]
----
The form in the denominator is (a+b)(a-b)
That product is always a^2 - b^2
---------------------
So for your problem you get:
[(-3+i)]/[3^2-(i)^2]
---
= (-3+i)/(9 + 1)
---
= (-3+i)/10
=================
That is the simplified form.
=================
Cheers,
Stan H.